Graph the Equation Y 1 2x 2

Y m x b y m x b. Since the equation is in ymxb form or slope-intercept form you graph this equation based on the slope and its y-intercept.

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Plot the y-intercept 00.

. Rewrite in slope-intercept form. Rewrite in slope-intercept form. Learn the steps on how to graph the equation of a line y -12x on a Cartesian graph.

If it gives you problems let me know. Step 4 - Find the y-intercept and the slope of the above equation. For more information refer to the link given below.

Y -1. Answer by tutorcecilia 2152 Show Source. Tap for more steps.

The point to get the graph of. Choose the correct graph below. Choose one of the equations and solve it for y by isolating y on the left hand side of the equal sign.

VB 4 4 2 2 0 0 -2 -2 4 - -4 0 0 2 6 Sketch the solution curve for the initial condition y 1 0. Y x2 2 y x 2 2. Two lines are parallel if they have the same slope m 1 m 2.

Use the slope-intercept form to find the slope and y-intercept. Tap for more steps. To graph this you first have to graph the y intercept which is given.

Find the values of m m and b b using the form y m x b y m x b. Use the slope-intercept form to find the slope and y-intercept. From 21 move up one space and over.

Y 1 2 x 1 y. To graph the given equation we make a table. Tap for more steps.

M is the slope which is 1 2 and b is the y intercept which is 5. Y 1 2 x 2 y 1 2 x 2. Combine 1 2 1 2 and x2 x 2.

Choose the correct graph below. Y 1 2 x y 1 2 x. Complete the square for x 2 2 x 2 2.

Find the properties of the given parabola. Now since your b is equal to -2 that is the value at which your line will intercept or cross the y-axis. -frac 1 2x 22xfrac 3 2-y0.

For y-intercept set colorredx0 giving. Y 2xcolorwhite2 colorgreeny2colorredxx02 - y2 So y-intercept is at the point xy02 For x-intercept set colorredy0 giving. Y 2x 1 y 2 x - 1.

Tap for more steps. Y 1 2x 2 y-1 2x - 4. Step 3 - Draw the graph of y x.

O maximum O minimum c Determine what value of x gives the optimal value of the function. Plug in some number for x and find out the value of y. It may take a few seconds to finish because it has to do lots of calculations.

It has not been well tested so have fun with it but dont trust it. Y 1 2x - x2 a Find the vertex of the graph of the equation. Y 1 2 x 1 y 1 2 x 1.

Y 2x - 3. Since the equation for slope intercept is ymxb. Y 1 2 x 2 y - 1 2 x - 2.

The slope-intercept form is y m x b y m x b where m m is the slope and b b is the y-intercept. Y - y 1 - mx - x 1. Tap for more steps.

Tap for more steps. The slope-intercept form is y m x b y m x b where m m is the slope and b b is the y-intercept. X y b Determine whether the vertex is a maximum or minimum point.

If you dont include an equals sign it will assume you mean 0. Y m x b y m x b. The point-slope form of a line with slope m and passing through the point x 1 y 1 is.

X y 2x-3-1 2-1-3 -5. Y m x b y m x b. Using the slope of 12 move up one space from 00 and move to the left two spaces.

Lets determine 2 points The line will cross the y axis at x0 and cross the x axis at y0 So we can determine these points intercepts by substitution. You can put this solution on YOUR website. Rewrite in slope-intercept form.

Plot point 2 1. 0 20 -3 -3. Tap for more steps.

Substitute -frac 1 2 for a 2 for b and frac 3 2-y for c in the quadratic formula frac -bsqrt b 2-4ac 2a. Step 1 - Write the given equation. Y 2x 2 y 2 x 2.

The slope-intercept form is y m x b y m x b where m m is the slope and b b is the y-intercept. Y 1 2 x 2 y 1 2 x 2. Choose one of the equations and solve it for y by isolating y on the left hand side of the equal sign.

Y m x b y m x b. Consider the following equation. Subtract y from both sides.

Y x 1 y 2 x 2. Use the form a x 2 b. The slope of a line containing the points P 1 x 1 y 1 and P 2 x 2 y 2 is given by.

Write in y m x b y m. 2 1 x 2 2 x 2 3 y 0. Step 5 - So the graph of the given equation is the line that passes through 0-1 and 320 and whose slope is m 23.

Y 1 2 x y 1 2 x. Y m x b y m x b. The slope-intercept form is y m x b y m x b where m m is the slope and b b is the y-intercept.

Note how m is the slope and b is the y-intercept. Y12x The slope is 12 the y-intercept is zero but isnt shown y 12x 0. Now you just have to focus on your slope which is 12.

The slope-intercept form is y m x b y m x b where m m is the slope and b b is the y-intercept. Rewrite the equation in vertex form. 1 Construct a slope field for the given differential equation.

Just remember M aka the number next to x is the slope and the number without any letter is the slope which is 5. Two lines are perpendicular if the product of their slopes is - lm 1 m 2 -1. Free graphing calculator instantly graphs your math problems.

Tap for more steps. Tap for more steps. 1 21 -2 -1.

Y m x b y m x b. The slope-intercept form is y m x b y m x b where m m is the slope and b b is the y-intercept. Add 1 on both sides.

Rewrite in slope-intercept form. Step 2 - Simplify the above equation. This equation is in standard form.

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